this is the answer We know the work we do on an object is calculated by multiplying the applied force and the distance it travels in the direction of motion. In this case, all the force is along the direction of motion, so the work is (2000N)*(0.2 m) = 400 J
21) the wedge in problem 20 acts like, slowly splitting the wood apart as it enters the log. the work you do in the wedge pushing it into the log, is the work it does on the wood, separating its two halves. if the two halves of the wedge only separate by distance of 0.05 m while the wedge travels 0.2m into the log, how much force is the wedge exerting on the two halves of the log to rip them apart.
please I need the answer so badly with explanation as well.
Thank you all
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